Question by ☮♥♫: Work and Energy Problem?
We’re working on work and energy right now, and I’m kind of confused. Here’s a problem we were assigned. I’m unsure on how to solve it. If you could help me out a bit (give me a hint or explain the steps), I would be so grateful! Thank you so much!

In 1936, Col. Harry Froboess of Switzerland jumped into the ocean from the airship Graf Hindenburg, which was 1.20 x 10² m above the water’s surface. Assiming Froboess had a mass of 72.0 kg, what was his kinetic energy at the moment he was 30.0 m from the water’s surface? What was his speed at that moment? Neglect the air resistance.

I know the formula for finding kinetic energy (KE = ½mv²) and potential energy (PE = mgh). But they don’t give you velocity, so I’m just kind of confused on how you would find the kinetic energy based on what they give you.

Any help would be great.
Thank you so much once again!

Best answer:

Answer by Kɥmǝr
Energy is conserved: E initial = E final

a) @ 30.0 m

mgh1 = mgh2 + 1/2mv^2

(72)(9.81)(1.20 x 10^2) – (72)(9.81)(30) = KE = 63 568.8 J

b) @ 30.0 m

KE = 1/2mv^2

v = sqrt((2KE)/m) = sqrt((2*63 568.8)/72)) = 42.02 m/s

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